Tuesday, October 11, 2011

Java Generics Tutorial - Part IV - Wildcards in Method Signatures and Bounded Type Variables

Part I - The Basics
Part II - Subtyping
Part III - Wildcards
Part IV - Bounded Type Variables

Long time no hear. In the previous parts of this blog post we learned what generics classes and methods are, how they behave in subtyping relations and how wildcards can be used to provide covariant and contravariant subtyping to generic types.
In this part of this series we will learn what bounded type variables are and the flexibility they provide.

Wildcards in Method Signatures

As seen in Part II of this series, in Java (as in many other typed languages), the Substitution principle stands: a subtype can be assigned to a reference of any of its supertypes.

This applies during the assignment of whichever reference, that is, even when passing parameters to a function or storing its result. One of the advantages of this principle, then, is that when defining class hierarchies, "general purpose" methods can be written to handle entire sub-hierarchies, regardless of the class of the specific object instances time being handled. In the Fruit class hierarchy we've used so far, a function that accepts a Fruit as a parameter will accept any of its subtypes (such as Apple or Strawberry).

As seen in the previous post, wildcards restore covariant and contravariant subtyping for generic types: using wildcards, then, let the developer write functions that can take advantage of the benefits presented so far.

If, for example, a developer wanted to define a method eat that accepted a List of whichever fruit, it could use the following signature:

void eat(List<? extends Fruit> fruits);

Since a List of whichever subtype of the class Fruit is a subtype of List<? extends Fruit>, the previous method will accept any such list as a parameter. Note that, as explained in the previous section, the Get and Put Principle (or the PECS Rule) will allow you to retrieve objects from such list and assign them to a Fruit reference.

On the other hand, if you wanted to put instances on the list passed as a parameter, you should use the ? super wildcard:

void store(List<? super Fruit> container);

This way, a List of whichever supertype of Fruit could be passed in to the store function and you could safely put whichever Fruit subtype into it.

Bounded Type Variables

The flexibility of generics is greater than this, though. Type variables can be bounded, pretty much in the same way wildcards can be (as we've seen in Part II). However, type variables cannot be bounded with super, but only with extends. Look at the following signature:

public static <T extends I<T>> void name(Collection<T> t);

It takes a collections of objects whose type is bounded: it must satisfy the T extends I<T> condition. Using bounded type variables may not seem more powerful than wildcards at first, but we'll detail the differences in a moment.

Let's suppose some, but not all, fruits in your hierarchy can be juicy as in:

public interface Juicy<T> {
    Juice<T> squeeze();
}

Juicy fruits will implement this interface and publish the squeeze method.

Now, you write a library method that takes a bunch of fruits and squeezes them all. The first signature you could write might be:

<T> List<Juice<T>> squeeze(List<Juicy<T>> fruits);

Using bounded type variables, you would write the following (which, indeed, has got the same erasure of the previous method):

<T extends Juicy<T>> List<Juice<T>> squeeze(List<T> fruits);

So far, so good. But limited. We could use the very same arguments used in the same posts and discover that the squeeze method is not going to work, for example, with a list of red oranges when:

class Orange extends Fruit implements Juicy<Orange>;
class RedOrange extends Orange;

Since we've already learned about the PECS principle, we're going to change the method with:

<T extends Juicy<? super T>> List<Juice<? super T>> squeezeSuperExtends(List<? extends T> fruits);

This method accepts a list of objects whose type extends Juicy<? super T>, that is, in other words, that there must exist a type S such that T extends Juicy<S> and S super T.

Recursive Bounds

Maybe you feel like relaxing the T extends Juicy<? super T> bound. This kind of bound is called recursive bound because the bound that the type T must satisfy depends on T. You can use recursive bounds when needed and also mix-and-match them with other kinds of bounds.

Thus you can, for example, write generic methods with such bounds:

<A extends B<A,C>, C extends D<T>>

Please remember that these examples are only given to illustrate what generics can do. Bounds you're going to use always depend on the constraints you're putting into your type hierarchy.

Using Multiple Type Variables

Let's suppose you want to relax the recursive bound we put on the last version of the squeeze method. Let's then suppose that a type T might extend Juicy<S> although T itself does not extends S. The method signature could be:

<T extends Juicy<S>, S> List<Juice<S>> squeezeSuperExtendsWithFruit(List<? extends T> fruits);

This signature has pretty much equivalent to the previous one (since we're only using T in the method arguments) but has got one slight advantage: since we've declared the generic type S, the method can return List<Juice<S> instead of List<? super T>, which can be useful in some situations, since the compiler will help you identify which type S is according to the method arguments you've passed. Since you're returning a list, chances are you want your caller to be able to get something from it and, as you've learned in the previous part, you can only get Object instances from a list such as List<? super T>


You can obviously add more bounds to S, if you need them, such as:


<T extends Juicy<S>, S extends Fruit> List<Juice<S>> squeezeSuperExtendsWithFruit(List<? extends T> fruits);

Multiple Bounds

What if you want to apply multiple bounds on the same type variable? It turns out that you can only write a bound per generic type variable. The following bounds are thus illegal:

<T extends A, T extends B> // illegal

The compiler will fail with a message such as:

T is already defined in...

Multiple bounds must be expressed with a different syntax, which turns out to be a pretty familiar notation:

<T extends A & B>

The previous bounds means that T extends both A and B. Please take into account that, according to the Java Language Secification, Chapter 4.4, states that a bound is either:
  • A type variable.
  • A class.
  • An interface type followed by further interface types.
This means that multiple bounds can only be expressed using interface types. There's no way of using type variables in a multiple bound and the compiler will fail with a message such as:

A type variable may not be followed by other bounds.

This is not always clear in the documentation I've read.






5 comments:

Anonymous said...

This Generics tutorial was the best in its species until I found Oracle java tutorial for java 8u20 (Last Updated 8/19/2014) oriented more toward dummies.
Thanks a lot Enrico.

Marek in Warsaw

Enrico Maria Crisostomo said...

Thank you very much Marek.

Florian Wicher said...

Isn't the last part of that method header superfluous?
> List> squeezeSuperExtends(List fruits);
couldn't I just write
> List> squeezeSuperExtends(List fruits);
instead? Why do I need a wildcard in the method argument? I can insert anything I want for T anyways...
I thought really long and hard about this, hope I am right. Thanks for your work :)

sathya said...

Generics tutorial provides the good usage of generic in Java

Thanks for your work

sathya said...

Generics provide the gentle introduction for its usage in Java

Thanks for your work